When sizing capacitors in series, what is the total capacitance using 12MFD and 15MFD capacitors?

When sizing capacitors in series, what is the total capacitance using 12MFD and 15MFD capacitors?

• A. 5.66 CT
• B. 6.35 CT
• C. 6.97 CT
• D. 6.66 CT

Answer: (D)

To determine the total capacitance of capacitors in series, the formula used is: \[ \frac{1}{C_{total}} = \frac{1}{C_1} + \frac{1}{C_2} + ... + \frac{1}{C_n} \] For two capacitors in series, the formula simplifies to: \[ \frac{1}{C_{total}} = \frac{1}{C_1} + \frac{1}{C_2} \] In this case, you have two capacitors: one with a capacitance of 12 microfarads (MFD) and another with a capacitance of 15 microfarads (MFD). Plugging in the values: \[ \frac{1}{C_{total}} = \frac{1}{12} + \frac{1}{15} \] To combine these fractions, you can find a common denominator. The least common multiple of 12 and 15 is 60. Therefore, you can rewrite the fractions: \[ \frac{1}{C_{total}} = \frac{5}{60} + \frac{4}{60} \] This gives: \[ \frac{1}{

To determine the total capacitance of capacitors in series, the formula used is:

[ \frac{1}{C_{total}} = \frac{1}{C_1} + \frac{1}{C_2} + ... + \frac{1}{C_n} ]

For two capacitors in series, the formula simplifies to:

[ \frac{1}{C_{total}} = \frac{1}{C_1} + \frac{1}{C_2} ]

In this case, you have two capacitors: one with a capacitance of 12 microfarads (MFD) and another with a capacitance of 15 microfarads (MFD).

Plugging in the values:

[ \frac{1}{C_{total}} = \frac{1}{12} + \frac{1}{15} ]

To combine these fractions, you can find a common denominator. The least common multiple of 12 and 15 is 60. Therefore, you can rewrite the fractions:

[ \frac{1}{C_{total}} = \frac{5}{60} + \frac{4}{60} ]

This gives:

[ \frac{1}{